Question 41: (text{Total }S={1+5+9+13+17+…+201} .)

Question 41: (text{Total }S={1+5+9+13+17+…+201} .) A. 3727 B. 5151 C. 7363 D. 2673 (begin{aligned}&text{The adjacent terms are separated by 4 units, so the number of terms is: }left[ {left( {201 – 1} right):4} right] + 1 = 51\ &text{Then sum S=}left[ {left( {201 + 1} right).51} right]:2 = 5151end{aligned}. ) ===============

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